Question #3c8ff

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Doc048
Apr 27, 2017

The unhybridized p-orbital would contain 'zero' electrons.

Explanation:

C[He]2s^2p_x^2p_y^0p_z^0 => ( C:[He]2uarr/(sp^2)uarr/(sp^2)uarr/(sp^2)2(0/p_z))^+ + e^-

The carbocation will combine with 3H(uarr/(1s))
=> CH_3^+[He]2((3sigma)(1p_z^0))^+

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Image Credit: Stefan V. (May 31, 2015)

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