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Question #3c8ff

1 Answer

Apr 27, 2017

The unhybridized p-orbital would contain 'zero' electrons.

Explanation:

C[He]2#s^2p_x^2p_y^0p_z^0# => ( C:[He]2#uarr/(sp^2)uarr/(sp^2)uarr/(sp^2)2(0/p_z))^+# + #e^-#

The carbocation will combine with 3H(#uarr/(1s)#)
=> #CH_3^+#[He]2((3#sigma)(1p_z^0))^+#

enter image source here

Image Credit: Stefan V. (May 31, 2015)

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