If there are $56 \cdot L$ $56*L$ of ozone, what molar quantity is present under standard conditions?

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If there are $56 \cdot L$ $56*L$ of ozone, what molar quantity is present under standard conditions?

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Answer 1 · 2017-04-25T19:40:56

Well, if it is pure ozone, there are approx. $2.5 \cdot m o l$ $2.5*mol$ of $O_{3} (g)$ $O_3(g)$ .

Explanation:

Under standard conditions of temperature and pressure, $273 \cdot K$ $273*K$ , and $1 \cdot a t m$ $1*atm$ , one mole of ideal gas occupies $22.4 \cdot L$ $22.4*L$ .

And thus we calculate the quotient..........

$\frac{56 \cdot L}{22.4 \cdot L \cdot m o l^{- 1}} = ? ? \cdot m o l$ $(56*L)/(22.4*L*mol^-1)=??*mol$

Note that ozone is a trace atmospheric gas, and you cannot get a bottle of ozone, as you would get a bottle of dioxygen, dinitrogen, etc.

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If there are $56 \cdot L$ $56*L$ of ozone, what molar quantity is present under standard conditions?

1 Answer

Explanation:

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Science

Math

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If there are 56⋅L56*L of ozone, what molar quantity is present under standard conditions?

1 Answer

Explanation:

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If there are $56 \cdot L$ $56*L$ of ozone, what molar quantity is present under standard conditions?