What molar quantity of #HCl# is there in a #24.38mL# volume of an aqueous solution that is #0.100mol*L^-1# with respect to #HCl#?

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Answer 1 · 2017-04-25T15:48:26

Approx. #25xx10^-4*mol#.

We use the relationship:

#"Concentration"# #=# #"Moles of solute"/"Volume of solution"#,

And typically, because we often use units of #"litres"# to express volume, #"concentration"# has units #"moles"*"L"^-1#.

And thus to assess the number of moles in a #24.38*mL# volume of #0.100*mol*L^-1# #HCl#, we simply assess the product:

#"Moles of solute"# #=# #"Concentration "xx" volume"#

#=24.38xx10^-3*cancelLxx0.100*mol*cancel(L^-1)=24.38xx10^-4*mol#.

And we need an equimolar quantity of #NaOH# to neutralize this molar quantity.

What molar quantity of #HCl# is there in a #24.38*mL# volume of an aqueous solution that is #0.100*mol*L^-1# with respect to #HCl#?