Question #96ae1

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Doc048 ยท Grace
Apr 25, 2017

Convert mass quantities to moles and divide by respective coefficients of balanced equation. The smaller number is the limiting reagent.

Explanation:

3H_2 + N_2 -> 2NH_3

Example: Assume Given 100 g of each reactant, what's the limiting reagent?

moles of H_2 = ((100g)/(2g mol^-1)) = 50 moles & Divide by '3' => 16.7

moles of N_2 = ((100g)/(28g mol^-1)) = 3.57 moles & Divide by '1' => 3.57

The limiting reagent is N_2 because after dividing by respective coefficients => 3.57 is smaller than 16.7 and H_2 will be in excess; after all N_2 is consumed in the reaction.

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