What are the molar ratios of reactants and products in dinitrogen reduction by dihydrogen?

1 Answer
anor277
May 1, 2017

Well, #"dinitrogen : dihydrogen : ammonia = 1 : 3 : 2".#

Explanation:

And thus the molar ratio follows the given stoichiometry of the reaction:

#N_2 + 3H_2(g) rarr 2NH_3(g)#

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