Question #a30bd

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Question #a30bd

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Answer 1 · 2017-04-24T01:12:47

$1.61 \cdot 10^{23}$ $1.61 * 10^23$ molecules of water.

Explanation:

This is a very simple chemistry question, and the explanation is as followed:

First, you want to calculate the molar mass of water. You can get the necessary information from the atomic weight of each element (see on the periodic table).
H2O = $(2 \cdot 1.01) + 16 = 18.02 \frac{g}{m o l}$ $(2 * 1.01) + 16 = 18.02 g / (mol)$

Now that you have found the molar mass, continue using dimensional analysis to find the answer. Also, note that I use the number $6.022 \cdot 10^{23} \frac{a t m s}{m o l}$ $6.022 * 10^23 (atms)/(mol)$ . This is Avogadro's number, and it will be very useful in chemistry.

$4.83 g (\frac{1 m o l}{18.02 g}) (\frac{6.022 \cdot 10^{23} a t m s}{1 m o l})$ $4.83 g ((1mol)/(18.02g))((6.022*10^23 atms)/(1 mol))$

All you have to do is plug this into your calculator, and you get
$1.61 \cdot 10^{23}$ $1.61 * 10^23$ molecules of water in 4.83 g with three significant figures.

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Question #a30bd

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