Question #51377

1 Answer
Dwight
Apr 27, 2017

This will require 2.067 litres of the acid solution.

Explanation:

In the equation, we see that 3 moles of #H_2# are produced when 3 moles of #H_2SO_4# are reacted. (This is seen from the coefficients placed before these formulas.)

To simply the relation, we can say that the ratio between #H_2SO_4# used and #H_2# produced is 1-to-1.

Now, we must convert the mass of #H_2# into moles:

#25.0 g -: 2.01588 g/"mol" = 12.40 "mol"#

Since the ratio is 1-to-1, this means we will require 12.40 mol of #H_2SO_4# to produce this hydrogen gas.

To determine the volume of the solution required, we start with the definition of molarity:

#"Molarity" = ("moles of solute")/("litres of solution")#

So,

#"litres of solution" = ("moles of solute")/("molarity") = (12.4 "mol")/(6.00 "mol"/L) = 2.067 L#

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