What is the electronic configuration of $F e^{3 +}$ $Fe^(3+)$ ion?

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What is the electronic configuration of $F e^{3 +}$ $Fe^(3+)$ ion?

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Answer 1 · 2017-04-22T08:47:51

Of the $ferric ion..........?$ $"ferric ion..........?"$

Explanation:

For $iron$ $"iron"$ , $Z = 26$ $Z=26$ , and thus for elemental iron we have to distribute 26 electrons by the aufbau scheme, and for $F e^{3 +}$ $Fe^(3+)$ , we must distribute 23 electrons..................And so:

$1 s^{2} 2 s^{2} 2 p^{6} 3 s^{2} 3 p^{6} 3 d^{5}$ $1s^(2)2s^(2)2p^(6)3s^(2)3p^(6)3d^(5)$ .

Note that a neutral iron atom has a configuration of.......

$1 s^{2} 2 s^{2} 2 p^{6} 3 s^{2} 3 p^{6} 4 s^{2} 3 d^{6}$ $1s^(2)2s^(2)2p^(6)3s^(2)3p^(6)4s^(2)3d^(6)$ (26 electrons as required.) However, upon oxidation, the $4 s$ $4s$ electrons are conceived to be removed FIRST, and this is typical for transition metal ions.

Would $F e (I I I)$ $Fe(III)$ complexes be paramagnetic? Why or why not........?

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What is the electronic configuration of $F e^{3 +}$ $Fe^(3+)$ ion?

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