How do we differentiate solutions of $sodium dichromate$ $"sodium dichromate"$ and $chromium (III+)$ $"chromium (III+)"$ ion?

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How do we differentiate solutions of $sodium dichromate$ $"sodium dichromate"$ and $chromium (III+)$ $"chromium (III+)"$ ion?

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Answer 1 · 2017-04-23T11:28:44

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Explanation:

Dichromate ion is $C r_{2} O_{7}^{2 -}$ $Cr_2O_7^(2-)$ . An oxygen bridges 2 metal centres to give a complex ion that I could represent as:

$^{-} O (_{2} O =) C r - O - C r {(= O)}_{2} O^{-}$ $""^(-)O(""_2O=)Cr-O-Cr(=O)_2O^(-)$ .

The oxidation state of each chromium centre is $V I +$ $VI+$ (the maximum oxidation number), and this reagent is commonly used an oxidant, and we see the colour of bright orange (the dichromate ion) change to green, $C r^{3 +}$ $Cr^(3+)$ .

![sites.google.com]( useruploads.socratic.org )

Dichromate salts are typically a beautiful orange colour:

![en.tjfuqiang.com]( useruploads.socratic.org )

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How do we differentiate solutions of $sodium dichromate$ $"sodium dichromate"$ and $chromium (III+)$ $"chromium (III+)"$ ion?

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Science

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How do we differentiate solutions of sodium dichromate"sodium dichromate" and chromium (III+)"chromium (III+)" ion?

1 Answer

Explanation:

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How do we differentiate solutions of $sodium dichromate$ $"sodium dichromate"$ and $chromium (III+)$ $"chromium (III+)"$ ion?