What is the resultant pH of the solution.....?

What is the resultant pH of the solution prepared by taking a 10*mL volume of HCl(aq) of 0.10*mol*L^-1 concentration, and diluting this to a 1*L volume?

1 Answer
anor277
Apr 21, 2017

pH=3

Explanation:

pH=-log_(10)[H_3O^+]

[H_3O^+]=(10xx10^-3*Lxx0.1*mol*L^-1)/(1*L)

10^-3*mol*L^-1

And thus pH=-log_(10)[H_3O^+]

-log_(10)(10^-3)=3...........

And I did this all without a calculator. Note that normally, we would always add acid to water, and not water to acid. However, here the acid concentration is sufficiently dilute to get away with reverse addition.

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