Question #a3c21

1 Answer
MeneerNask
Apr 18, 2017

The molar mass of #CH_4=12+4xx1=16#
and the molar mass of #CO_2=12+2xx16=44#

Explanation:

All gasses have the same molar volume, so we may say that the mass ratio is #m(CO_2)divm(CH_4)=44div16=11div4#

The mass percentage : #m%(CO_2)=11/(11+4)xx100%=73%#

(rounded figures have been used)

Related questions
See all questions in Percent Composition
Impact of this question
1449 views around the world
You can reuse this answer
Creative Commons License