Question #6b172

1 Answer
Nathan L.
Jun 2, 2017

We're asked to find the liters of #"Cl"_2# occupied by #6.7# #"g Cl"_2#.

What we can do here is calculate the number of moles of chlorine using the molar mass of #"Cl"_2#, #70.90"g"/"mol"#:

#6.7# #cancel("g Cl"_2)((1"mol Cl"_2)/(70.90cancel("g Cl"_2))) = 0.0945# #"mol Cl"_2#

At standard temperature and pressure, one mole of any gas occupies a volume of #22.41# #"L"#. (from Avogadro's law). We can use this fact to convert from moles to liters:

#0.0945cancel("mol Cl"_2)((22.41"L Cl"_2)/(1cancel("mol Cl"_2))) = color(red)(2.1)# #color(red)("L Cl"_2)#

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