Question #152d2

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Answer 1 · 2017-04-16T03:00:07

See the entire solution process below:

First, let's call the amount of flour that will be needed: #f#

We can write the rations as:

#7:6 -> 650:f# or

#7/6 = 650/f# or

#6/7 = f/650#

Now, multiply each side of the equation by #color(red)(650)# to solve for #f# while keeping the equation balanced:

#color(red)(650) xx 6/7 = color(red)(650) xx f/650#

#3900/7 = cancel(color(red)(650)) xx f/color(red)(cancel(color(black)(650)))#

#557 = f#

Russ will 557 mg of flour rounded to the nearest mg.