$$6000$ are partly invested at $5%$ and partly at at $9%$ . If interest earned in a year is $$400$ , what are amounts invested at $5%$ and at $9%$ ?

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Answer 1 · 2017-04-14T05:47:24

Amount invested at $5%$ is $$3,500$ and amount invested at $9%$ is $$2,500$

Let the amount invested at $5%$ be $x$ , then amount invested at $9%$ will be $6000-x$ .

Therefore, interest earned on $5%$ is $(5x)/100$ and interest earned on $9%$ is $(6000-x)9/100$ . As total interest is $$400$ , we have

$(5x)/100+9/100(6000-x)=400$

or $5x+9(6000-x)=40000$

or $5x+54000-9x=40000$

or $-4x=-14000$

$x=(-14000)/(-4)=3500$

Hence amount invested at $5%$ is $$3,500$ and amount invested at $9%$ is $6000-3500=$2,500$

$6000$6000 are partly invested at 5%5% and partly at at 9%9%. If interest earned in a year is $400$400, what are amounts invested at 5%5% and at 9%9%?