What is the de Broglie wavelength for a "0.01 kg" particle moving at "10 m/s""?

1 Answer
Apr 15, 2017

I got: 6.63xx10^-33m

Explanation:

We know that the deBroglie wavelength is:

lambda=h/p

where:

  • h=6.63xx10^-34 "J"cdot"s" is Planck's constant;
  • p=mv is the linear momentum.

We get:

lambda=(6.63xx10^-34)/(0.01*10)=6.63xx10^-33 "m",

too small to be detected by any device.

This is indicative of a large, non-quantum system.