What is the de Broglie wavelength for a "0.01 kg" particle moving at "10 m/s""?
1 Answer
Apr 15, 2017
I got:
Explanation:
We know that the deBroglie wavelength is:
lambda=h/p
where:
h=6.63xx10^-34 "J"cdot"s" is Planck's constant;p=mv is the linear momentum.
We get:
lambda=(6.63xx10^-34)/(0.01*10)=6.63xx10^-33 "m" ,
too small to be detected by any device.
This is indicative of a large, non-quantum system.