Question #004f2

1 Answer
Apr 12, 2017

0.56

Explanation:

1 molar solution =#"Number of moles of solute"/"Volume of solution"#
for Sugar
#C_(12)H_(22)O_(11)# molar mass=342#gm#
according to equation and information provided
#1=(3.42/342)/x#
where x is the volume of solution in #l#
#:.# the volume of solution is 0.01 #l#
which is 10 #ml#
#:.#10 gm of water .
moles of solute=#3.42/342=0.01#
moles of solution =#10/18=0.55#
#:.# the mole fraction of the solution is #0.01/(0.01+0.55)#