What mass is represented by 14.8*mol "barium chromate", and by 1.23xx10^22 chlorine molecules?

1 Answer
Apr 12, 2017

We have under 4*kg of "barium chromate"............and under 2*g of Cl_2.

Explanation:

The molar mass of "barium chromate" is 253.37*g*mol^-1. And thus the mass of the given quantity is 14.8*cancel(mol)xx253.37*g*cancel(mol^-1)=3750*g.

For the Cl_2 molecule, we solve the quotient:

(1.23xx10^22*"chlorine molecules")/(6.022xx10^23*"chlorine molecules"*mol^-1)=0.0204*mol.

Since the chlorine molecule has a molar mass of 70.90*g*mol^-1, the mass of dichlorine is 70.90*g*mol^-1xx0.0204*mol=1.45*g