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Question #5b4da

1 Answer

Apr 12, 2017

#0#

Explanation:

Remember that #cot(theta)=1/tan(theta)#.

Then, #cot(90^@)=1/tan(90^@)#. Recall that #tan(90^@)=oo#. Then, #cot(90^@)=1/tan(90^@)=1/oo=0#.

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