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Question #6e833

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1 Answer

Apr 11, 2017

Solve the equation.

Explanation:

The conclusion of MVT says there is a #c# in #(1/2,2)# such that #f'(c) = (f(2)-f(1/2))/(2-(1/2))#

Find #f'(x) = 1+1/x^2# and #f(2)-f(1/2))/(2-(1/2)) = 2#.

The solutions to # 1+1/x^2 = 2# are #-1# and #1#, but #c# is in #(1/2,2)#, so the only value for #c# is #1#.

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