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Question #57682

1 Answer

Apr 16, 2017

See below

Explanation:

#y=arcsin(cot(x^-2))#

#siny=cot(x^-2)#

#(cosy)y'=-(2csc^2(x^-2))/x^3#

#y'=-(2csc^2(x^-2))/(x^3cosy)#

#cosy=+-sqrt(1-sin^2y)=+-sqrt(1-cot^2(x^-2))#

#y'=+-(2csc^2(x^-2))/(x^3sqrt(1-cot^2(x^-2))) #

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