Question #93d8b
1 Answer
Explanation:
First, let me give you 2 equations which are going to be useful in helping us solve this problem
Where
The image formed is a real image and is double in size compared to the object. One thing to understand about real images is that when you have a real image, it is always inverted (upside down) .
![https://useruploads.socratic.org/4dJ2edjiTf2OjqcToXFW_microscope-diagram-and-functions-ray_diagram_sample.jpg)
If we know the image is double in size, this means its magnification is
m = -(i)/om=−io -2 = -((cancel+i))/((cancel+o)) -2 = -(i)/o
We only are given focal length and nothing else.
But, we can use the magnification equation to express what the
-2 = -(i)/o -2o = -i cancel-2o = cancel-i 2o = i
Now, take the thins lens equation and express
Note: We don't have to convert
-
1/12 = 1/o + 1/i -
1/12 = 1/o + 1/(2o) -
1/12 = 2/(2o) +1/(2o) -
1/12 = 3/(2o) (2o)/12 = 3 2o = 3*12 2o = 36 o = (36)/(2) o = 18
Answer =