Question #12f8c

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Question #12f8c

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Answer 1 · 2017-04-07T20:20:30

$pi/3$ . $pi$ , and $(5pi)/3$ , if you meant to leave out the $0$ . If you want all the critical numbers on a full period, then include $0$ or $2pi$ .

Explanation:

$f'(x) = 2sinxcosx-sinx = sinx(2cosx-1)$

#f'(x) is nevern undefined and

$f'(x) = 0$ at

$sinx = 0$ or $cosx = 1/2$ .

This leads to solutions $x=0$ , $x=pi$ , $x=pi/3$ and $x=(5pi)/3$

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