Question #24dc7

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Question #24dc7

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Answer 1 · 2017-04-06T05:52:58

$C = r + s (t - 3)$ $C=r+s(t-3)$

Explanation:

The cost $C$ $C$ of the call will be $r$ $r$ cents for the initial 3 minutes plus the time $t$ $t$ multiplied by the rate $s$ $s$ .

Since you have already paid for the first three minutes, that time will need to be deducted from the overall time $t$ $t$ before it is multiplied by the rate $s$ $s$ .

So if $t > 3$ $t>3$ , your cost will be: #C=r+s(t-3)

Example: $t = 5, r = $ 3, s = $ 2$ $t=5, r=$3, s=$2$

$C = $ 3 + $ 2 (5 - 3) = $ 3 + $ 2 \times 2 = $ 3 + $ 4 = $ 7$ $C=$3+$2(5-3) = $3+$2xx2 = $3+$4 = $7$

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Question #24dc7

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