Question #4d92c

Question

933 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2017-04-05T21:22:36

#= 2 (1 + j sqrt3), -4 , 2(1 - j sqrt3)#

#(64(cos(pi)+jsin(pi)))^(1/3)#

#= 64^(1/3) (cis(pi + 2n pi))^(1/3)#

#= 4 (e^(j \ (pi + 2n pi)))^(1/3)#

#= 4 e^(j (pi+ 2n pi)/3)#

Working through the #n#'s:

#= 4 e^(j (pi)/3), 4 e^(j pi), 4 e^(j (5 pi)/3)#

They start repeating after that.

#= 4 \ cis ((pi)/3), 4 \ cis ( pi), 4 \ cis (5 pi)/3#

#= 2 (1 + j sqrt3), -4 , 2(1 - j sqrt3)#