Question #7cea5
1 Answer
Apr 11, 2017
Explanation:
#sum_(n=0)^oo(1+2^n)/3^n#
#=sum_(n=0)^oo1/3^n+2^n/3^n#
#=sum_(n=0)^oo((1/3)^n+(2/3)^n)#
#=sum_(n=0)^oo(1/3)^n+sum_(n=0)^oo(2/3)^n#
Then, use the sum of the geometric series formula:
#=1/(1-1/3)+1/(1-2/3)#
#=3/2+3#
#=9/2#
