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Question #b8119

1 Answer

Apr 3, 2017

#e^(e^x) + C#

Explanation:

Use the exponent rule #x^(m+n) = x^mx^n#:

#int e^(x+e^x) dx = int e^x e^(e^x) dx#

Let #u = e^x#, #du = e^x dx#

#int e^x e^(e^x) dx = int e^u du = e^u + C = e^(e^x) + C#

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