Question #ad1b3

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Question #ad1b3

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Answer 1 · 2017-04-04T04:21:44

$7 x (x + 1)$ $7x(x + 1)$

Explanation:

$\frac{10}{7 x}, \frac{2}{x + 1}$ $10/(7 x), 2/(x + 1)$

$L C D = L C M (7 x, x + 1)$ $LCD = LCM (7 x, x+1)$

$(7 x, x + 1)$ $(7 x, x+1)$ $\to$ $->$ divide with $7 \to (x, x + 1)$ $7 -> (x , x +1)$

$(x, x + 1)$ $(x, x+1)$ $\to$ $->$ divide with $x \to (1, x + 1)$ $x-> (1 , x +1)$

$(1, x + 1)$ $(1, x+1)$ $\to$ $->$ divide with $x + 1 \to (1, 1)$ $x + 1 -> (1 , 1)$

$L C D = L C M (7 x, x + 1) = 7 \cdot x \cdot (x + 1) = 7 x (x + 1)$ $LCD = LCM (7 x, x+1) = 7*x*(x+1) = 7x(x+1)$

$\frac{10}{7 x}, \frac{2}{x + 1}$ $10/(7 x), 2/(x + 1)$ $= \frac{10 (x + 1)}{7 x (x + 1)}$ $= (10(x+1))/(7x(x+1)$ , $\frac{2 \cdot 7 x}{(x + 1) \cdot 7 x}$ $(2*7x)/((x + 1)*7 x)$

$= \frac{10 x + 10}{7 x (x + 1)}$ $= (10x+10)/(7x(x+1)$ , $\frac{14 x}{(x + 1) \cdot 7 x}$ $(14x)/((x + 1)*7 x)$

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Question #ad1b3

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