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Answer 1 · 2017-11-12T13:44:23

$a = 35, b = 10, c = 29.443$
$/_A = 116, /_B = 14.88, /_C = 49.12$

Law of sines $a/sin A = b / sin B = c / sin C$

$35 / sin 116^0 = 10 / sin B$

$sin B = (10 * sin 116^0) / 35$

$/_B = 14.88^0$
$/_C = 180 - 116 - 14.88 = 49.12^0$

$c / sin C =b / sin B$
$c = b * (sin C / sin B)$

$c = 10*(sin 49.12/ sin 14.88)$

$c = 29.443$

$a = 35, b = 10, c = 29.443$
$/_A = 116, /_B = 14.88, /_C = 49.12$