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Answer 1 · 2017-04-02T11:21:25

#500.#

Recall that Arithmetic Mean (AM) of #a_1,a_2,a_3,...,a_n# is

#AM=(a_1+a_2+a_3+...+a_n)/n#

We are given the following set of nos. :

#5, 10, 15, 20, ..., 995.#

To find, how many these nos. are, we observe their patern :

#5(1), 5(2), 5(3), 5(4), ..., 5(199) rArr n=199.#

By the Formula for Sum of #n# terms of Arith. Seq.,

we get,

#AM=(5+10+15+20+...+995)/199#

#={199/2(5+995)}-:199#

#:. AM=500.#

Enjoy Maths.!