Question #e845d

1 Answer
Apr 2, 2017

27.1g of CaO contains 2.92 x 10^23molecules.

Explanation:

This is a problem of stoichiometry.

The molar mass of CaO = 40+16 grams, i.e. 56 grams.

Now, the Avogadro number =6.023x10^23.

So, 56g of CaO contains 6.023 x 10^23 molecules.

:.27.1g of CaO contains 2.92 x 10^23molecules. (Answer).

**Hope it Helps :) **