Question #d7127

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Question #d7127

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Answer 1 · 2017-04-01T16:06:28

$speed of train is : 18.53 \frac{m}{s}$ $"speed of train is :"18.53" "m/s$

Explanation:

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$As the train moves on curvilinear path,a centrifugal force$ $"As the train moves on curvilinear path,a centrifugal force"$
$occurs on the pendulum bob.$ $"occurs on the pendulum bob."$

$tan θ = \frac{m \cdot \frac{v^{2}}{r}}{m g}$ $tan theta=(m*v^2/r)/(mg)$

$tan theta=cancel(m)*v^2/r*1/(cancel(m)g)$

$tan theta=v^2/(r g)$

$v^2=r g tan theta$

$v:"speed of train"$

$r:400 m$

$theta:5^o$

$g:9.81" "N/(kg)$

$v^2=400*9.81*tan 5^o$

$v^2=343.31$

$v=sqrt(343.31)$

$v=18.53" "m/s$

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Question #d7127

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