A chromium chloride salt contains $32.8 %$ $32.8%$ metal content by mass. What is its empirical formula?

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A chromium chloride salt contains $32.8 %$ $32.8%$ metal content by mass. What is its empirical formula?

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Answer 1 · 2017-03-30T20:34:58

We assume a $100 \cdot g$ $100*g$ mass of compound, and get an empirical formula of $C r C l_{3}$ $CrCl_3$ .

Explanation:

In all problems of this sort, it is convenient to assume a $100 \cdot g$ $100*g$ mass of compound, and then work out the individual molar quantities of each element:

$Moles of chromium = \frac{32.8 \cdot g}{52.0 \cdot g \cdot m o l^{- 1}} = 0.631 \cdot m o l$ $"Moles of chromium"=(32.8*g)/(52.0*g*mol^-1)=0.631*mol$

$Moles of chlorine = \frac{67.2 \cdot g}{35.45 \cdot g \cdot m o l^{- 1}} = 1.90 \cdot m o l$ $"Moles of chlorine"=(67.2*g)/(35.45*g*mol^-1)=1.90*mol$

We divide thru by the SMALLEST molar quantity, that of the metal, to get an empirical formula of $C r C l_{3}$ $CrCl_3$ .

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A chromium chloride salt contains $32.8 %$ $32.8%$ metal content by mass. What is its empirical formula?

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Science

Math

Humanities

... and beyond

A chromium chloride salt contains 32.8%32.8% metal content by mass. What is its empirical formula?

1 Answer

Explanation:

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Impact of this question

A chromium chloride salt contains $32.8 %$ $32.8%$ metal content by mass. What is its empirical formula?