Question #53d32

Question

1205 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2017-03-29T11:40:31

# 58975/20736, or, -58975/20736.#

#x+1/x=2 1/12=25/12.#

# rArr (x^2+1)/x=25/12.#

# rArr 12x^2+12=25x.#

# rArr 12x^2-25x+12=0.#

# rArr 12x^2-16x-9x+12=0,...[16xx9=144, 16+9=25].#

# rArr 4x(3x-4)-3(3x-4)=0.#

# rArr (3x-4)(4x-3)=0.#

# rArr x=4/3, or, x=3/4.#

#x=4/3rArrx^4-1/x^4=(4/3)^4-(3/4)^4=256/81-81/256=58975/20736.#

#x=3/4rArrx^4=1/x^4=(3/4)^4-(4/3)^4=-58975/20736.#

Enjoy Maths.!