Question #f1b76

1 Answer
anor277
Mar 29, 2017

H3CCH2CH(CH3)C(=O)H

Explanation:

So draw the parent hydrocarbyl chain (four carbons long for butyl):

C1−C2−C3−C4

Substitute in the functional groups at the appropriate position. It is an aldehyde so it has a carbonyl at the head of the line. At C2 we substitute a methyl group as required.

H(O=)C1C2(CH3)C3−C4

Satisfy carbon's quadrivalency (add hydrogens):

H(O=)C−CH(CH3)−CH2−CH3

The exercise is a hell of a lot easier on paper than by using an editor like this one. You will find these sorts of problems trivial in a week or so.

Would this molecule have left and right handed isomers? Why?

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