Question #c895d

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Answer 1 · 2017-03-31T18:07:37

I got #7634#

Have a look:
enter image source here

So at #t=10# we get:
#y(10)=10,000e^(-0.027*10)=7633.79~~7634#

Answer 2 · 2017-03-31T18:08:31

7627

Treat this the same way you do for compound interest. Only it is minus the percentage rather than plus

So #" "P(1+x)^n" becomes "P(1-x)^n#

Thus we have:

set #1-x" as "X# giving

#10000(X)^6=8500#

So we need to determine #X#

#(X)^6=8500/10000 = 0.85#

Taking logs:#" "# I choose the logs of #" "ln ->log_e#

#6ln(X)=ln(0.85)#

#ln(X)=ln(0.85)/6#

#X=ln^(-1)(ln(0.85)/6) =0.97327...#
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
So for 10 days we have

#10000(0.97327...)^10 = 7627.195...#

Call this 7627

The 0.195.. means that those people are still alive but 'on the road' to death.