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Answer 1 · 2017-08-30T12:37:26

The magnetic field produced is proportional linearly to the magnitude of the electric current. Thus, larger the current is, the stronger is the induced magnetic field.

$- \to d B = \frac{μ_{0}}{4 π} \frac{I \to d l X \to R}{R^{3}}$ $vec(dB) = mu_0/(4pi)(Ivec(dl) X vec R)/R^3$

This gives magnetic induction for a conducting vector element $\to d l$ $vec(dl)$ carrying current $I$ $I$ at a distance $\to R$ $vec R$ from $\to d l$ $vec(dl)$ .

This is Biot-Savart's law.

This shows how the magnetic field $- \to d B$ $vec(dB)$ is proportional to the current $I$ $I$ .

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