Simplify? #((16x^2)/(8x))/((4x^2)/(16x))#

1 Answer
Rachel · MathFact-orials.blogspot.com
Mar 27, 2017

#8#

Explanation:

I'm not sure. but I think your question is about a complex fraction
#((16x^2)/(8x))/((4x^2)/(16x)) =(16x^2)/(8x)xx(16x)/(4x^2)#.

From here, we should expand all the components so that #(16x^2)/(8x)xx(16x)/(4x^2)=(4*2*2*x*x)/(2*4*x)*(4*4*x)/(4*x*x)#

Now we just need to simplify
#(cancel(4)*cancel(2)*2*cancel(x)*x)/(cancel(2)*cancel(4)*cancel(x))# #(cancel(4)*4*cancel(x))/(cancel(4)*cancel(x)*x)#

That leaves us with #(2*x)*4/x#, which we can simplify to #(8x)/x# or just #8#.

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