How many ions result from the dissolution of a 11.1*g mass of calcium chloride in water?

1 Answer
anor277
Mar 27, 2017

Approx. 1.81xx10^23 ions

Explanation:

"Moles of calcium chloride" = (11.1*g)/(110.98*g*mol^-1)=0.100*mol

And thus in solution:

CaCl_2(s) + "excess "H_2OrarrCa^(2+) + 2Cl^(-), there are 0.100*mol Ca^(2+) ions, and 0.200*mol Cl^(-) ions, i.e. 0.300*mol of ions...........

And 0.300*molxxN_A=0.300*molxx6.022xx10^23*mol^-1

1.81xx10^23 ions..........

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