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Answer 1 · 2017-08-04T01:04:20

I got a bit more than $8"min"$

Light in vacuum travels at a speed $c=3xx10^8m/s$ .
A beam of light must travel:
$(93xx10^6)/0.62=1.5xx10^8km=1.5xx10^11m$

We can find the time remembering that:

$"speed"="distance"/"time"$

So:
$"time"=(1.5xx10^11)/(3xx10^8)=500s$

corresponding to:

$8"min"$ and $20s$

Answer 2 · 2017-08-04T01:05:41

About 8 minute and 20 second.

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