Question #6bb3a

Question

1690 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2017-03-26T00:05:13

Given

#H_2(s) + F_2(g)->2HF(g)color(blue)(.....[1]), DeltaH_1= -537#

#C(s) + 2F_2(g)-> CF_4(g)color(blue)(.....[2]), DeltaH_2= -680#

#2C(s) + 2H_2(g) -> C_2H_4(g)color(blue)(.....[3]), DeltaH_3= +52.3#

To Calculate #DeltaH# for the reaction

#C_2H_4(g) + 6F_2(g)->2CF_4(g) + 4HF(gcolor(blue)(.....[4]),DeltaH_4=?#

#"eq[1]"xx2+"eq[2]"xx2-"eq[3]"# gives

#DeltaH_4=2xxDeltaH_1+2xxDeltaH_2-DeltaH_3#

#=>DeltaH_4=2xx(-537)+2xx(-680)-52.3=-2486.3#