Question #f8e22

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Answer 1 · 2017-03-26T00:23:05

Given

$2C(s)+O_2(g)->2CO(g)color(red)(......[1]), Delta H_1= -221.0 kJ$

$2C(s)+O_2(g)+4H_2(g)-> 2CH_3OH(g)color(red)(......[2]), Delta H_2= -402.4 kJ$

To calculate $DeltaH_3$ for

$CO(g) + 2H_2(g)->CH_3OH(g)color(red)(......[3]),DeltaH_3=?$

$1/2(Eq[2]-Eq[1])$ gives

$DeltaH_3=1/2(DeltaH_2-DeltaH_1)=1/2(-402+221)=-90.5kJ$