Question #28e8a

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Question #28e8a

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Answer 1 · 2017-03-26T22:45:33

The escape velocity is the one giving enough kinetic energy to balance gravitational energy exactly, so its total energy is zero
$\frac{1}{2} m v^{2} = G M \frac{m}{r}$ $1/2mv^2 = GMm/r$

Explanation:

$v = \sqrt{2 G \frac{M}{r}}$ $v=sqrt{2GM/r}$
$v = \sqrt{2 (6.67 \times 10^{- 11}) \frac{5.1 \times 10^{24}}{57.0 \times 10^{5}}} = 1.09 \times 10^{4} \frac{m}{s}$ $v=sqrt(2(6.67xx10^-11)(5.1xx10^24)/(57.0xx10^5))= 1.09xx10^4 m/s$

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