Question #0540f

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Answer 1 · 2017-03-25T03:40:55

The velocity is $8.37xx10^6m/s$

The relation here is

$p = h/(lambda)$

where $lambda$ is the wavelength of the electron.

Also, since the classical definition of momentum states that

$p=mv$

We can write

#mv=h/(lambda)

or $v=h/(mlambda)$

Now the numbers

$v= (6.63xx10^(-34))/((9.1 xx10^(-31))(8.7xx10^(-11))$ $=8.37xx10^6m/s$