Question #17e5c

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Question #17e5c

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Answer 1 · 2017-03-22T22:45:29

Train B

Explanation:

Let's focus on Train B. Train B's initial velocity is $8m/s$ and acceleration is $1m/s^2$ . We also have $t=10$ We need Train B's final velocity:

Use the equation $a=(vf-vi)/t$

$1=(vf-8)/10$

$10=vf-8$

$vf=18m/s$

$18m/s$ is greater than $16m/s$ so Train B goes faster.

Answer 2 · 2017-03-26T06:58:51

Train B

Explanation:

Train A's speed is constant so its speed after 10 seconds would be $16 m/s$ , but train B which starts at $8 m/s$ accelerates at $1 m/s^2$
so after 10 seconds it picks up additional $10 m/s$ of speed to $18 m/s$ . Hence B will have greater speed.

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Question #17e5c

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