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Answer 1 · 2017-03-21T16:20:55

The temperature was #=49.52ºC#

Let #T=# final temperature of the water

For the water, # Delta T_w=50-T#

# m_w C_w (DeltaT_w)=2#

#C_w=4.186kJkg^-1K^-1#

#1*4.186*(50-T)=2#

#50-T=2/4.186#

#50-T=0.48#

#T=50-0.48#

#T=49.52ºC#