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Answer 1 · 2017-03-27T15:44:23

#4627J# or #4.6 kJ#

Recognize the equation to use

#q=m*c*DeltaT#

We know the mass(#m#)- #66.7g#

We know the specific heat capacity(#c#)-#0.75J/(g˚C)#

We can find #DeltaT# from

#DeltaT=T_2 - T_1=92.5-0#

#DeltaT=92.5˚C#

#:.q= 66.7cancelg*0.75J/cancel(g˚C)*92.5cancel(˚C)#

#rArrq=4627J or 4.6kJ#

To get #kJ#, simply multiply by #10^-3# or divide by #1000#

This is how

#4627cancelJ*(1kJ)/(1000cancelJ)#

#OR#

#4627*10^-3kJ#