Question #f36b9

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Question #f36b9

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Answer 1 · 2018-01-25T05:47:05

Refer explanation.

Explanation:

Given -

$y=x^4+8x^3$

To graph, a function, first find the turning points.
Find the first derivative and set it to zero, so that you know the value of $x$ , the slope of the curve becomes zero.

$dy/dx=4x^3+24x^2$

$dy/dx=0=>4x^3+24x^2=0$

$4x^2(x+6)=0$

$4x^2=0$

$x=0$

$x=-6$

At $x=0$ and at $x=-6$ , there are turning points.
Take a range of values that includes 0 and -6. Calculate the corresponding value of $y$ . Tabulate them. Use the pair of the points to obtain the curve.

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At $x=0$ , there is a point of inflexion.
At $x=-8$ , the curve reaches the minimum.

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Question #f36b9

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