Question #40a2f

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Question #40a2f

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Answer 1 · 2017-03-24T10:23:48

(a) $0^@$
Since the magnitude of resultant is equal to the sum of magnitudes of two displacements.
$|vecR|=|vecA|+|vecB|$

(b) $180^@$
Since the magnitude of resultant is equal to the difference of magnitudes of two displacements. (assuming $|vecA|>|vecB|$ )
$|vecR|=|vecA|-|vecB|$
(b) $90^@$
Since the square of magnitude of resultant is equal to sum of squares of magnitudes of two displacements. This is true only in case of a right triangle.
$|vecR|^2=|vecA|^2+|vecB|^2$

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