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Question #c5781

1 Answer

Mar 18, 2017

The answer is #=x^3/3+x+C#

Explanation:

We apply

#intx^ndx=x^(n+1)/(n+1)+C(n!=-1)#

Therefore,

#int(x^2+1)dx#

#=intx^2dx+int1*dx#

#=x^3/3+x+C#

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