How many unpaired electrons in ${[Co {(CN)}_{6}]}_{6}^{3 -}$ $["Co"("CN")_6]^(3-)$ ?

Question

How many unpaired electrons in ${[Co {(CN)}_{6}]}_{6}^{3 -}$ $["Co"("CN")_6]^(3-)$ ?

1 Answer

Impact of this question

7650 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2017-03-17T19:27:33

$The number is ZERO...........$ $"The number is ZERO..........."$

Explanation:

$C o^{3 +}$ $Co^(3+)$ has a $d^{6}$ $d^6$ electronic configuration.......and these are classically LOW SPIN, especially with strong field ligands such as cyanide.........

${[C o {(C \equiv N)}_{6}]}_{6}^{3 -}$ $[Co(C-=N)_6]^(3-)$ is thus diamagnetic with no unpaired electrons.

Science

Math

Humanities

... and beyond

How many unpaired electrons in ${[Co {(CN)}_{6}]}_{6}^{3 -}$ $["Co"("CN")_6]^(3-)$ ?

1 Answer

Explanation:

Related questions

Impact of this question

Science

Math

Humanities

... and beyond

How many unpaired electrons in [Co(CN)6]3−["Co"("CN")_6]^(3-)?

1 Answer

Explanation:

Related questions

Impact of this question

How many unpaired electrons in ${[Co {(CN)}_{6}]}_{6}^{3 -}$ $["Co"("CN")_6]^(3-)$ ?